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sdk/tests/language/super/operator_test.dart
T
Robert Nystrom c9d54c12f6 Reformat tests/language/s** using 3.8 style.
Change-Id: I3c5cfbc1bc5e41d2ef1598427067dea00f9f42b4
Reviewed-on: https://dart-review.googlesource.com/c/sdk/+/425403
Reviewed-by: Lasse Nielsen <lrn@google.com>
Commit-Queue: Lasse Nielsen <lrn@google.com>
Auto-Submit: Bob Nystrom <rnystrom@google.com>
2025-05-02 04:46:00 -07:00

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Dart

// Copyright (c) 2011, the Dart project authors. Please see the AUTHORS file
// for details. All rights reserved. Use of this source code is governed by a
// BSD-style license that can be found in the LICENSE file.
// Dart test for testing super operator calls
import "package:expect/expect.dart";
class A {
String val = "";
List things;
A() : things = ['D', 'a', 'r', 't', 42];
operator +(String s) {
val = "${val}${s}";
return this;
}
operator [](i) {
return things[i];
}
operator []=(i, val) {
return things[i] = val;
}
}
class B extends A {
operator +(String s) {
super + ("${s}${s}"); // Call A.operator+(this, "${s}${s}").
return this;
}
operator [](i) {
var temp = super[i];
if (temp is String) {
return "$temp$temp";
}
return temp + temp;
}
operator []=(i, val) {
// Make sure the index expression is only evaluated
// once in the presence of a compound assignment.
return super[i++] += val;
}
}
main() {
var a = new A();
a = a + "William"; // operator + of class A.
Expect.equals("William", a.val);
Expect.equals("r", a[2]); // operator [] of class A.
a = new B();
a += "Tell"; // operator + of class B.
Expect.equals("TellTell", a.val);
Expect.equals("rr", a[2]); // operator [] of class B.
a[4] = 1; // operator []= of class B.
Expect.equals(43, a.things[4]);
Expect.equals(86, a[4]);
}