0b58c4bd10
Retain the old values. Reapply of https://dart-review.googlesource.com/c/sdk/+/20680 with fixes for VM method fingerprints. Change-Id: Ie14e7ccc3194d5561983348e6b6752728913ff4d Reviewed-on: https://dart-review.googlesource.com/20664 Reviewed-by: Erik Ernst <eernst@google.com> Commit-Queue: Lasse R.H. Nielsen <lrn@google.com>
40 lines
1.1 KiB
Dart
40 lines
1.1 KiB
Dart
// Copyright (c) 2013, the Dart project authors. Please see the AUTHORS file
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// for details. All rights reserved. Use of this source code is governed by a
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// BSD-style license that can be found in the LICENSE file.
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// Test canonicalization of simple arithmetic equivalences.
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// VMOptions=--optimization-counter-threshold=20 --no-use-osr --no-background-compilation
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import "package:expect/expect.dart";
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main() {
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for (var i = 0; i < 50; i++) {
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Expect.isTrue(mul1double(i) is double);
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Expect.equals(i.toDouble(), mul1double(i));
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Expect.equals(0.0, mul0double(i));
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Expect.equals(i.toDouble(), add0double(i));
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Expect.equals(i, mul1int(i));
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Expect.equals(i, add0int(i));
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Expect.equals(0, mul0int(i));
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Expect.equals(0, and0(i));
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Expect.equals(i, and1(i));
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Expect.equals(i, or0(i));
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Expect.equals(i, xor0(i));
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}
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Expect.isTrue(mul0double(double.nan).isNaN);
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Expect.isFalse(add0double(-0.0).isNegative);
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}
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mul1double(x) => 1.0 * x;
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mul0double(x) => 0.0 * x;
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add0double(x) => 0.0 + x;
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mul1int(x) => 1 * x;
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mul0int(x) => 0 * x;
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add0int(x) => 0 + x;
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and0(x) => 0 & x;
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or0(x) => 0 | x;
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xor0(x) => 0 ^ x;
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and1(x) => (-1) & x;
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