Paul Berry
8f1ca007f2
The inferred types for const expressions shouldn't refer to type variables that are in scope, because at runtime those type variables may take on different values at different times (meaning the const expression isn't actually const after all). Test cases are in inference_new, since analyzer implements incorrect behavior. Fixes #30677. Change-Id: I27b9a95a92557ad1ce1c2c0f28d9a760c372d52a Reviewed-on: https://dart-review.googlesource.com/5298 Reviewed-by: Konstantin Shcheglov <scheglov@google.com>
28 lines
945 B
Dart
28 lines
945 B
Dart
// Copyright (c) 2017, the Dart project authors. Please see the AUTHORS file
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// for details. All rights reserved. Use of this source code is governed by a
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// BSD-style license that can be found in the LICENSE file.
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/*@testedFeatures=inference*/
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library test;
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typedef V F<U, V>(U u);
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class Foo<T> {
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Bar<T> get v1 => const /*@typeArgs=Null*/ Bar();
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Bar<List<T>> get v2 => const /*@typeArgs=List<Null>*/ Bar();
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Bar<F<T, T>> get v3 => const /*@typeArgs=(Object) -> Null*/ Bar();
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Bar<F<F<T, T>, T>> get v4 =>
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const /*@typeArgs=((Null) -> Object) -> Null*/ Bar();
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List<T> get v5 => /*@typeArgs=Null*/ const [];
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List<F<T, T>> get v6 => /*@typeArgs=(Object) -> Null*/ const [];
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Map<T, T> get v7 => /*@typeArgs=Null, Null*/ const {};
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Map<F<T, T>, T> get v8 => /*@typeArgs=(Object) -> Null, Null*/ const {};
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Map<T, F<T, T>> get v9 => /*@typeArgs=Null, (Object) -> Null*/ const {};
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}
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class Bar<T> {
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const Bar();
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}
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main() {}
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