0672317bec
Committed: https://code.google.com/p/dart/source/detail?r=18575 Reverted: http://code.google.com/p/dart/source/detail?r=18576 Review URL: https://codereview.chromium.org//12212213 git-svn-id: https://dart.googlecode.com/svn/branches/bleeding_edge/dart@18579 260f80e4-7a28-3924-810f-c04153c831b5
442 lines
13 KiB
Dart
442 lines
13 KiB
Dart
// Copyright (c) 2011, the Dart project authors. Please see the AUTHORS file
|
|
// for details. All rights reserved. Use of this source code is governed by a
|
|
// BSD-style license that can be found in the LICENSE file.
|
|
|
|
part of dart.core;
|
|
|
|
/**
|
|
* The [Iterable] interface allows to get an [Iterator] out of an
|
|
* [Iterable] object.
|
|
*
|
|
* This interface is used by the for-in construct to iterate over an
|
|
* [Iterable] object.
|
|
* The for-in construct takes an [Iterable] object at the right-hand
|
|
* side, and calls its [iterator] method to get an [Iterator] on it.
|
|
*
|
|
* A user-defined class that implements the [Iterable] interface can
|
|
* be used as the right-hand side of a for-in construct.
|
|
*/
|
|
abstract class Iterable<E> {
|
|
const Iterable();
|
|
|
|
/**
|
|
* Create an [Iterable] that generates its elements dynamically.
|
|
*
|
|
* The [Iterators] created by the [Iterable] will count from
|
|
* zero to [:count - 1:] while iterating, and call [generator]
|
|
* with that index to create the next value.
|
|
*
|
|
* As an [Iterable], [:new Iterable.generate(n, generator)):] is equivalent to
|
|
* [:const [0, ..., n - 1].map(generator):]
|
|
*/
|
|
factory Iterable.generate(int count, E generator(int index)) {
|
|
return new _GeneratorIterable<E>(count, generator);
|
|
}
|
|
|
|
/**
|
|
* Returns an [Iterator] that iterates over this [Iterable] object.
|
|
*/
|
|
Iterator<E> get iterator;
|
|
|
|
/**
|
|
* Returns a lazy [Iterable] where each element [:e:] of [this] is replaced
|
|
* by the result of [:f(e):].
|
|
*
|
|
* This method returns a view of the mapped elements. As long as the
|
|
* returned [Iterable] is not iterated over, the supplied function [f] will
|
|
* not be invoked. The transformed elements will not be cached. Iterating
|
|
* multiple times over the the returned [Iterable] will invoke the supplied
|
|
* function [f] multiple times on the same element.
|
|
*/
|
|
Iterable map(f(E element)) => new MappedIterable<E, dynamic>(this, f);
|
|
|
|
/**
|
|
* Returns a lazy [Iterable] with all elements that satisfy the
|
|
* predicate [f].
|
|
*
|
|
* This method returns a view of the mapped elements. As long as the
|
|
* returned [Iterable] is not iterated over, the supplied function [f] will
|
|
* not be invoked. Iterating will not cache results, and thus iterating
|
|
* multiple times over the the returned [Iterable] will invoke the supplied
|
|
* function [f] multiple times on the same element.
|
|
*/
|
|
Iterable<E> where(bool f(E element)) => new WhereIterable<E>(this, f);
|
|
|
|
|
|
/**
|
|
* Expand each element of this [Iterable] into zero or more elements.
|
|
*
|
|
* The resulting Iterable will run through the elements returned
|
|
* by [f] for each element of this, in order.
|
|
*
|
|
* The returned [Iterable] is lazy, and will call [f] for each element
|
|
* of this every time it's iterated.
|
|
*/
|
|
Iterable expand(Iterable f(E element)) =>
|
|
new ExpandIterable<E, dynamic>(this, f);
|
|
|
|
/**
|
|
* Check whether the collection contains an element equal to [element].
|
|
*/
|
|
bool contains(E element) {
|
|
for (E e in this) {
|
|
if (e == element) return true;
|
|
}
|
|
return false;
|
|
}
|
|
|
|
/**
|
|
* Applies the function [f] to each element of this collection.
|
|
*/
|
|
void forEach(void f(E element)) {
|
|
for (E element in this) f(element);
|
|
}
|
|
|
|
/**
|
|
* Reduce a collection to a single value by iteratively combining each element
|
|
* of the collection with an existing value using the provided function.
|
|
* Use [initialValue] as the initial value, and the function [combine] to
|
|
* create a new value from the previous one and an element.
|
|
*
|
|
* Example of calculating the sum of a collection:
|
|
*
|
|
* collection.reduce(0, (prev, element) => prev + element);
|
|
*/
|
|
dynamic reduce(var initialValue,
|
|
dynamic combine(var previousValue, E element)) {
|
|
var value = initialValue;
|
|
for (E element in this) value = combine(value, element);
|
|
return value;
|
|
}
|
|
|
|
/**
|
|
* Returns true if every elements of this collection satisify the
|
|
* predicate [f]. Returns false otherwise.
|
|
*/
|
|
bool every(bool f(E element)) {
|
|
for (E element in this) {
|
|
if (!f(element)) return false;
|
|
}
|
|
return true;
|
|
}
|
|
|
|
/**
|
|
* Convert each element to a [String] and concatenate the strings.
|
|
*
|
|
* Converts each element to a [String] by calling [Object.toString] on it.
|
|
* Then concatenates the strings, optionally separated by the [separator]
|
|
* string.
|
|
*/
|
|
String join([String separator]) {
|
|
Iterator<E> iterator = this.iterator;
|
|
if (!iterator.moveNext()) return "";
|
|
StringBuffer buffer = new StringBuffer();
|
|
if (separator == null || separator == "") {
|
|
do {
|
|
buffer.add("${iterator.current}");
|
|
} while (iterator.moveNext());
|
|
} else {
|
|
buffer.add("${iterator.current}");
|
|
while (iterator.moveNext()) {
|
|
buffer.add(separator);
|
|
buffer.add("${iterator.current}");
|
|
}
|
|
}
|
|
return buffer.toString();
|
|
}
|
|
|
|
/**
|
|
* Returns true if one element of this collection satisfies the
|
|
* predicate [f]. Returns false otherwise.
|
|
*/
|
|
bool any(bool f(E element)) {
|
|
for (E element in this) {
|
|
if (f(element)) return true;
|
|
}
|
|
return false;
|
|
}
|
|
|
|
List<E> toList() => new List<E>.from(this);
|
|
Set<E> toSet() => new Set<E>.from(this);
|
|
|
|
/**
|
|
* Returns the number of elements in [this].
|
|
*
|
|
* Counting all elements may be involve running through all elements and can
|
|
* therefore be slow.
|
|
*/
|
|
int get length {
|
|
int count = 0;
|
|
Iterator it = iterator;
|
|
while (it.moveNext()) {
|
|
count++;
|
|
}
|
|
return count;
|
|
}
|
|
|
|
/**
|
|
* Find the least element in the iterable.
|
|
*
|
|
* Returns null if the iterable is empty.
|
|
* Otherwise returns an element [:x:] of this [Iterable] so that
|
|
* [:x:] is not greater than [:y:] (that is, [:compare(x, y) <= 0:]) for all
|
|
* other elements [:y:] in the iterable.
|
|
*
|
|
* The [compare] function must be a proper [Comparator<T>]. If a function is
|
|
* not provided, [compare] defaults to [Comparable.compare].
|
|
*/
|
|
E min([int compare(E a, E b)]) {
|
|
if (compare == null) compare = Comparable.compare;
|
|
Iterator it = iterator;
|
|
if (!it.moveNext()) return null;
|
|
E min = it.current;
|
|
while (it.moveNext()) {
|
|
E current = it.current;
|
|
if (compare(min, current) > 0) min = current;
|
|
}
|
|
return min;
|
|
}
|
|
|
|
/**
|
|
* Find the largest element in the iterable.
|
|
*
|
|
* Returns null if the iterable is empty.
|
|
* Otherwise returns an element [:x:] of this [Iterable] so that
|
|
* [:x:] is not smaller than [:y:] (that is, [:compare(x, y) >= 0:]) for all
|
|
* other elements [:y:] in the iterable.
|
|
*
|
|
* The [compare] function must be a proper [Comparator<T>]. If a function is
|
|
* not provided, [compare] defaults to [Comparable.compare].
|
|
*/
|
|
E max([int compare(E a, E b)]) {
|
|
if (compare == null) compare = Comparable.compare;
|
|
Iterator it = iterator;
|
|
if (!it.moveNext()) return null;
|
|
E max = it.current;
|
|
while (it.moveNext()) {
|
|
E current = it.current;
|
|
if (compare(max, current) < 0) max = current;
|
|
}
|
|
return max;
|
|
}
|
|
|
|
/**
|
|
* Returns true if there is no element in this collection.
|
|
*/
|
|
bool get isEmpty => !iterator.moveNext();
|
|
|
|
/**
|
|
* Returns an [Iterable] with at most [n] elements.
|
|
*
|
|
* The returned [Iterable] may contain fewer than [n] elements, if [this]
|
|
* contains fewer than [n] elements.
|
|
*/
|
|
Iterable<E> take(int n) {
|
|
return new TakeIterable<E>(this, n);
|
|
}
|
|
|
|
/**
|
|
* Returns an [Iterable] that stops once [test] is not satisfied anymore.
|
|
*
|
|
* The filtering happens lazily. Every new [Iterator] of the returned
|
|
* [Iterable] will start iterating over the elements of [this].
|
|
* When the iterator encounters an element [:e:] that does not satisfy [test],
|
|
* it discards [:e:] and moves into the finished state. That is, it will not
|
|
* ask or provide any more elements.
|
|
*/
|
|
Iterable<E> takeWhile(bool test(E value)) {
|
|
return new TakeWhileIterable<E>(this, test);
|
|
}
|
|
|
|
/**
|
|
* Returns an [Iterable] that skips the first [n] elements.
|
|
*
|
|
* If [this] has fewer than [n] elements, then the resulting [Iterable] will
|
|
* be empty.
|
|
*/
|
|
Iterable<E> skip(int n) {
|
|
return new SkipIterable<E>(this, n);
|
|
}
|
|
|
|
/**
|
|
* Returns an [Iterable] that skips elements while [test] is satisfied.
|
|
*
|
|
* The filtering happens lazily. Every new [Iterator] of the returned
|
|
* [Iterable] will iterate over all elements of [this].
|
|
* As long as the iterator's elements do not satisfy [test] they are
|
|
* discarded. Once an element satisfies the [test] the iterator stops testing
|
|
* and uses every element unconditionally.
|
|
*/
|
|
Iterable<E> skipWhile(bool test(E value)) {
|
|
return new SkipWhileIterable<E>(this, test);
|
|
}
|
|
|
|
/**
|
|
* Returns the first element.
|
|
*
|
|
* If [this] is empty throws a [StateError]. Otherwise this method is
|
|
* equivalent to [:this.elementAt(0):]
|
|
*/
|
|
E get first {
|
|
Iterator it = iterator;
|
|
if (!it.moveNext()) {
|
|
throw new StateError("No elements");
|
|
}
|
|
return it.current;
|
|
}
|
|
|
|
/**
|
|
* Returns the last element.
|
|
*
|
|
* If [this] is empty throws a [StateError].
|
|
*/
|
|
E get last {
|
|
Iterator it = iterator;
|
|
if (!it.moveNext()) {
|
|
throw new StateError("No elements");
|
|
}
|
|
E result;
|
|
do {
|
|
result = it.current;
|
|
} while(it.moveNext());
|
|
return result;
|
|
}
|
|
|
|
/**
|
|
* Returns the single element in [this].
|
|
*
|
|
* If [this] is empty or has more than one element throws a [StateError].
|
|
*/
|
|
E get single {
|
|
Iterator it = iterator;
|
|
if (!it.moveNext()) throw new StateError("No elements");
|
|
E result = it.current;
|
|
if (it.moveNext()) throw new StateError("More than one element");
|
|
return result;
|
|
}
|
|
|
|
/**
|
|
* Returns the first element that satisfies the given predicate [f].
|
|
*
|
|
* If none matches, the result of invoking the [orElse] function is
|
|
* returned. By default, when [orElse] is `null`, a [StateError] is
|
|
* thrown.
|
|
*/
|
|
E firstMatching(bool test(E value), { E orElse() }) {
|
|
// TODO(floitsch): check that arguments are of correct type?
|
|
for (E element in this) {
|
|
if (test(element)) return element;
|
|
}
|
|
if (orElse != null) return orElse();
|
|
throw new StateError("No matching element");
|
|
}
|
|
|
|
/**
|
|
* Returns the last element that satisfies the given predicate [f].
|
|
*
|
|
* If none matches, the result of invoking the [orElse] function is
|
|
* returned. By default, when [orElse] is [:null:], a [StateError] is
|
|
* thrown.
|
|
*/
|
|
E lastMatching(bool test(E value), {E orElse()}) {
|
|
// TODO(floitsch): check that arguments are of correct type?
|
|
E result = null;
|
|
bool foundMatching = false;
|
|
for (E element in this) {
|
|
if (test(element)) {
|
|
result = element;
|
|
foundMatching = true;
|
|
}
|
|
}
|
|
if (foundMatching) return result;
|
|
if (orElse != null) return orElse();
|
|
throw new StateError("No matching element");
|
|
}
|
|
|
|
/**
|
|
* Returns the single element that satisfies [f]. If no or more than one
|
|
* element match then a [StateError] is thrown.
|
|
*/
|
|
E singleMatching(bool test(E value)) {
|
|
// TODO(floitsch): check that argument is of correct type?
|
|
E result = null;
|
|
bool foundMatching = false;
|
|
for (E element in this) {
|
|
if (test(element)) {
|
|
if (foundMatching) {
|
|
throw new StateError("More than one matching element");
|
|
}
|
|
result = element;
|
|
foundMatching = true;
|
|
}
|
|
}
|
|
if (foundMatching) return result;
|
|
throw new StateError("No matching element");
|
|
}
|
|
|
|
/**
|
|
* Returns the [index]th element.
|
|
*
|
|
* If [this] [Iterable] has fewer than [index] elements throws a
|
|
* [RangeError].
|
|
*
|
|
* Note: if [this] does not have a deterministic iteration order then the
|
|
* function may simply return any element without any iteration if there are
|
|
* at least [index] elements in [this].
|
|
*/
|
|
E elementAt(int index) {
|
|
if (index is! int || index < 0) throw new RangeError.value(index);
|
|
int remaining = index;
|
|
for (E element in this) {
|
|
if (remaining == 0) return element;
|
|
remaining--;
|
|
}
|
|
throw new RangeError.value(index);
|
|
}
|
|
}
|
|
|
|
|
|
typedef E _Generator<E>(int index);
|
|
|
|
class _GeneratorIterable<E> extends Iterable<E> {
|
|
final int _count;
|
|
final _Generator<E> _generator;
|
|
_GeneratorIterable(this._count, this._generator);
|
|
Iterator<E> get iterator => new _GeneratorIterator(_count, _generator);
|
|
}
|
|
|
|
class _GeneratorIterator<E> implements Iterator<E> {
|
|
final int _count;
|
|
final _Generator<E> _generator;
|
|
int _index = 0;
|
|
E _current;
|
|
|
|
_GeneratorIterator(this._count, this._generator);
|
|
|
|
bool moveNext() {
|
|
if (_index < _count) {
|
|
_current = _generator(_index);
|
|
_index++;
|
|
return true;
|
|
} else {
|
|
_current = null;
|
|
return false;
|
|
}
|
|
}
|
|
|
|
E get current => _current;
|
|
}
|
|
|
|
/**
|
|
* An [Iterator] that allows moving backwards as well as forwards.
|
|
*/
|
|
abstract class BiDirectionalIterator<T> extends Iterator<T> {
|
|
/**
|
|
* Move back to the previous element.
|
|
*
|
|
* Returns true and updates [current] if successful. Returns false
|
|
* and sets [current] to null if there is no previous element.
|
|
*/
|
|
bool movePrevious();
|
|
}
|